College Math CLEP Prep Practice Exam

Disable ads (and more) with a membership for a one time $2.99 payment

Unlock your mathematical potential and conquer the College Math CLEP exam with ease! Introducing our powerful College Math CLEP Prep Practice Exam, your ultimate tool for exam readiness.

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.

What is the equation for a circle with a radius of 5 and a center of (3,4)?

(x-3)^2 + (y-4)^2 = 25
(x-3)^2 + (y-4)^2 = 5
(x+3)^2 + (y+4)^2 = 25
(x+3)^2 + (y+4)^2 = 5

The correct answer is: (x-3)^2 + (y-4)^2 = 25

The equation for a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) represents the center of the circle and r is the radius. Therefore, the equation for a circle with a radius of 5 and a center of (3,4) would be (x-3)^2 + (y-4)^2 = 25. Option A is the only answer that satisfies this equation. Option B, (x-3)^2 + (y-4)^2 = 5, would result in a much smaller circle with a radius of approximately 2.24. Option C and D have incorrect centers and hence do not represent a circle with the given radius. Therefore, A is the correct answer.