College Math CLEP Prep Practice Exam

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If the roots of a second degree equation are -2 and 5, what is the equation?

x2 – 2 = -5
x2 – 2x + 5 = 0
x2 + 2x + 5 = 0
x2 + 2 = 5

The correct answer is: x2 + 2x + 5 = 0

The equation must be in the form of ax^2 + bx + c = 0, where a, b, and c are constants. In a second degree equation, the highest exponent is 2, meaning there must be an x^2 term in the equation. Option A and D only have one term with an x in it and do not have an x^2 term, so they cannot be the equation. Option B has an x^2 term and a constant term, but the coefficient of x^2 is 1, which means the roots would be -5 and 5, not -2 and 5 as given. Therefore, the correct equation is C, as it has an x^2 term, an x term with a coefficient of 2, and a constant term of 5, which gives the roots of -2 and 5